Proof 1 2 3 4 N 1 12

A recursive evaluation of zeta of negative integers by luboš motl. Euler s proof that 1 2 3 1 12 by john baez. à la différence de son homologue la série alternée des.

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2010年4月22日閲覧 the euler maclaurin formula bernoulli numbers the zeta function and real variable analytic continuation by terence tao.

Proof 1 2 3 4 n 1 12. Ramanujan was being a bit naughty in private correspondence with hardy who was meant to be amused and intrigued but it has escaped into the wild where people who don t. L addition de tous les nombres entiers positifs donne 1 12. People found the idea so astounding that it even made. A recursive evaluation of zeta of negative integers by luboš motl.

The euler maclaurin formula bernoulli numbers the zeta function and real variable analytic continuation by terence tao. For those of you who are unfamiliar with this series which has come to be known as the ramanujan summation after a famous indian. The idea featured in a numberphile video see below which claims to prove the result and also says that it s used all over the place in physics. Maths then the answer to this sum is 1 12.

One can get out of them what one wants if one uses them and it is they which have made so much unhappiness and so many paradoxes. A première vue oui mais quand on y regarde de plus près on découvre l une des plus b. John baez september 19 2008. Elle n est pas non plus sommable au sens de cesàro.

Euler s proof that 1 2 3 1 12 by john baez. Divergent series are on the whole devil s work and it is a shame that one dares to found any proof on them. Srinivasa ramanujan 1887 1920 was an indian mathematician.

La série a pour terme général n sa n ième somme partielle est donc le nombre triangulaire s n 1 2 n égal à n n 1 2 la suite s n tend vers l infini. Recently a very strange result has been making the rounds. It says that when you add up all the natural numbers maths 1 2 3 4. Can one think of anything more appalling than to say that 0 1 2 2n 3 2n 4 2n etc.

La série n est donc pas convergente elle ne possède donc pas de somme au sens usuel du terme. There is no ramanujan s proof to agree with or disagree with.